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2021 · Section 1 · Multiple choice

Question 7

[1 mark] Simple familiar
Game planPremium2.1 The machine chain
The question

A pulley system with an efficiency of 75% is used to vertically raise a 120 kg load a distance of 3 m. If the length of pulley rope pulled to raise the load is 8 m, the effort required is

Not quite. 330 N is the perfect-machine effort, 441 N, multiplied by 0.75. A machine that wastes energy needs more effort than a perfect one, so the efficiency has to make the effort bigger. In 2021, 14.6% of Queensland students chose (A).

Not quite. 392 N is $1176\div3$. It uses the 3 m lift as the VR and leaves out the efficiency. The VR is the 8 m of rope over the 3 m of lift. In 2021, 11.7% of Queensland students chose (B).

Not quite. 440 N is close to 441 N, the effort a perfect machine would need, $1176\div\frac{8}{3}$. It leaves out the 75%, and a real machine needs more effort than that. In 2021, 15.2% of Queensland students chose (C).

That is it. Step through the hints below to see why. In 2021, 57.9% of Queensland students chose (D).

forces to scale 120 kg FL = 1176 N work out and work in, to scale work out = 1176 × 3 = 3528 J

Velocity ratio
Use the 75%

The load is a mass, so turn it into a force. There is no diagram to count ropes on, so the VR comes from the two distances.

$$\begin{aligned}F_L&=mg=120\times9.8\\[6pt]&=1176\text{ N}\\[6pt]\text{VR}&=\frac{d_E}{d_L}=\frac{8}{3}=2.67\end{aligned}$$

Using the 3 m lift on its own as the VR leads to (B).

Rearrange the efficiency formula for MA, with $\eta$ as a decimal.

$$\begin{aligned}\text{MA}&=\eta\times\text{VR}\\[6pt]&=0.75\times\frac{8}{3}=2\end{aligned}$$

Keep the VR as the fraction $\frac{8}{3}$ and the MA comes out exactly 2. The MA is smaller than the VR, as it must be for a real machine.

Now the effort comes from the MA.

$$F_E=\frac{F_L}{\text{MA}}=\frac{1176}{2}=588\text{ N}$$

Check it against a perfect machine, which would need $1176\div\frac{8}{3}=441$ N. A 75% machine needs more effort than that, so (A) and (C) are both too small.

$$\begin{aligned}\text{MA}&=0.75\times\frac{8}{3}=2\\[6pt]F_E&=\frac{120\times9.8}{2}=588\text{ N}\end{aligned}$$

VR from the distances, MA from the efficiency, then the effort from the MA. The work check agrees: $588\times8=4704$ J in for $1176\times3=3528$ J out is 75%.

(D)
How Queensland students answered in 2021
(A)
14.6%
(B)
11.7%
(C)
15.2%
(D)
57.9%

The most common wrong answer was (C), the effort for a perfect machine with the 75% left out. (A) was close behind, with the efficiency applied the wrong way. Ask whether a lossy machine should need more effort or less.

Only mark this done when you could do it without help. Reading the solution does not count.

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Question wording and any figures are from the 2021 QCAA Engineering external assessment, © State of Queensland (QCAA) 2021, licensed under CC BY 4.0, and have been adapted, except where a third-party source is named. Tangent Tuition is not affiliated with the QCAA.